8266 internal timer interrupt: not exiting despite timer.deinit()

Q&A Forum › 8266 internal timer interrupt: not exiting despite timer.deinit()

Enzo Pontone asked 4 years ago

HI, please anyone could help me to understand why this sample code behaves this way:
it correctly waits 3 secs, prints “on_timer” and stays in the while loop (I checked this with a print inside it) because exit_flag is never set to 1 despite it’s global. Thanks for your help!

https://pastebin.com/az40hXN2

4 Answers

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Sara Santos Staff answered 4 years ago

Hi.

On line 6 you have:

exit_flag == 1

And it should be

exit_flag = 1

With only one “=”

Additionally, you are having a problem with global variable definition. Try this code, it will work as expected:

https://pastebin.com/UCZUP4nm

This discussion explains what was going on with your variable: https://forum.micropython.org/viewtopic.php?t=4814

I hope this solves your problem.

Regards,
Sara

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Enzo Pontone answered 4 years ago

Thanks Sara,
after some hours I’d better rest for a while: I rellay didn’t see the == 🙂
Regarding the global question: I see it works if I only declare the global in the callback (without the main declaration).
Can this lead to other problems?

0 Vote Up Vote Down

Sara Santos Staff answered 4 years ago

Hi again.
I’m not sure. I think it depends on your code.
Regards,
Sara

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Enzo Pontone answered 4 years ago

Ok, thanks!
Nice regards!