David Barker asked 6 months ago
I have buttons and a slider in a websocket server programme and a two void notifyCients wich conflict
void notifyClients(String sliderValues) {
ws.textAll(sliderValues);
}
and]
void notifyClients2(String state) {
ws.textAll(state);
}
can join both in one void statement
regards Dave
Sara Santos Staff answered 6 months ago
Hi.
What do you mean by conflict?
You need to be more specific. Can you provide more details?
Regards,
Sara
David Barker answered 6 months ago
Hi Sara
please find link to code
https://docs.google.com/document/d/1IOpTmpmXArOr5HuGfhx1p_AWgGZwqnGdcFGDXiOAoX8/edit?usp=sharing
hope this works
regards
Sara Santos Staff answered 6 months ago
Hi again.
I’m currently away from home and I can’t test your code.
Please share the exact issues that you get and errors so that it’s easier to understand why it doesn’t work.
Regards,
Sara
David Barker answered 6 months ago
HI
The error I am getting is
src\main.cpp:81:6: note: ‘void notifyClients(String)’ previously defined here
void notifyClients(String sliderValues) {
I think the problem is that I have two ‘void notifyClient’ values
void notifyClients(String sliderValues) {
ws.textAll(sliderValues);
}
and]
void notifyClients2(String state) {
ws.textAll(state);
}
thanks for your help
regards Dave
Sara Santos Staff answered 6 months ago
You can’t have multiple functions with the same name.
Each function needs to have a unique name.
Regards,
Sara
Sara Santos Staff answered 5 months ago
Let me know if you need further help to continue with your project.
Regards,
Sara